
Function Block Library 4–54
1336 FORCE — 5.9 August 1995
Example 1 — Horizontal Scale = 1S/Division
A UP/DWN CNTR Output
+32767 "
–32767 "
0 "
A–––––––––––––––––––––––– 7.4 Seconds ––––––––––––––––––––––––"
Preset = +32767
Select = 0
UD1 = 2048
Time = 240mS
Inc = 1
Dec = 0
Min = –32767
Max = +32767
The number of iterations required to decrement the output from it’s Preset value of +32767
to the Min value of –32767 would be:
Total Iterations = Range ÷ Increment = 65534 ÷ 2048 = 31.99 ≈ 31.
The time it takes to traverse from a Max setting of +32767 to –32767 would be:
Total Time = Total Iterations ÷ Time Input = 31 × 240mS = 7.44 S or approximately 7.4S.
Example 2 — Horizontal Scale = 1S/Division
UP/DWN CNTR Output "
+32767 "
–32767 "
0 "
A–––––––––––––––––––––––– 7.4 Seconds ––––––––––––––––––––––––"
Preset = –32767
Select = 0
UD1 = 2048
Time = 240mS
Inc = 0
Dec = 1
Min = –32767
Max = +32767
Example 2 is similar to Example 1 except the UP/DWN CNTR must count up from a Preset
value of –32767.
UP/DWN CNTR
(continued)
Commenti su questo manuale